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Moles

Masses or Volumes from Electrolysis.

A unit of electrical charge is called a Coulomb.
One Coulomb (symbol Q) is 6·2 x 10¹⁸ electrons.

One mole of electrons is the same as 96,500 Coulombs.
96,500 Coulombs is called a Faraday.

Electric current (symbol I) is a flow of electrical charge.
The rate of flow of electrical charge is measured in amps (A).
One amp is one Coulomb per second.    Q = I x t.

Example 3.

The electrolysis of molten lead bromide - PbBr₂
produces lead at  the cathode and bromine at the anode.

A current of 10 amps is allowed to flow
through molten lead bromide for 5 hours.
What mass of lead is deposited at the cathode?

Method.
1) Write the half equation for the electrolysis.
Pb²⁺  +    2e^-          Pb
2 moles of electrons (2 Faradays) are required to deposit 1 mole of lead.

2) Find how many Faradays have passed through
the lead bromide in 5 hours.

Q = I x t

5 hours contains (5 x 60 x 60) seconds
= 18,000 seconds.

Q = 10 x 18,000
                = 180,000 Coulombs.

1 Faraday = 96,500 coulombs.
180,000 coulombs = 180,000 ÷ 96,500 Faradays
= 1·865 Faradays.

3) From the proportion in 1, 2 Faradays are required to deposit 1 mole of lead.
1·865 faradays will deposit (1·865 ÷ 2) moles of lead,
= 0·933 moles of lead.

mass = moles x RAM

RAM of lead = 207

mass = 0·933 x 207
             = 193 g  of lead.

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